Math, asked by rahulsiddu9036, 1 year ago

anybody distance formula section formula and area formula​

Answers

Answered by rihan99
2

Answer:

[tex] \sqrt{ (xb - xa+ (yb - ya)} \: \\ this \: is \: a \: \: distance \: formula \\ m1x2 + m2x1 \div m1 + m2 \: \: \: m1y2 + m2y1 \div m1 + m2 \\ \frac{1}{2} {x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)[/tevx]

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Answered by Mysterioushine
5

● Distance between any two points (x₁,y₁) & (x₂,y₂) is given by

\large\rm\bold{\boxed{D\:=\:\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}}

● Section Formula when it is divided internally in the ratio m:n joining the points (x₁,y₁) & (x₂,y₂) is given by

\large\rm\bold{\boxed{(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}}}

● Section formula when it is divided externally in the ratio m:n joining the points (x₁,y₁) , (x₂,y₂) is given by

\large\rm\bold{\boxed{(\frac{mx_2-nx_1}{m-n},\frac{my_2-ny_1}{m-n})}}

● Area of triangle is with vertices (x₁,y₁) , (x₂,y₂) &(x₃,y₃) is given by

\large\rm\bold{\boxed{\frac{x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2}{2})}}

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