Question

Anybody give me answer of this question ​

Answer 1

i.   (x + y)3 = x3 + y3 + 3xy(x + y)

⇒ (x + y)3 – 3(x + y)(xy) = x3 + y3

⇒ (x + y)[(x + y)2-3xy] = x3 + y3

⇒ (x + y)(x2 + y2 – xy) = x3 + y3

Hence, verified.

(ii) ∵ (x – y)3 = x3 – y3 – 3xy(x – y)

⇒ (x – y)3 + 3xy(x – y) = x3 – y3

⇒ (x – y)[(x – y)2 + 3xy)] = x3 – y3

⇒ (x – y)(x2 + y2 + xy) = x3 – y3

Hence, verified.

Answer 2

Answer:

please follow me

Step-by-step explanation:

please mark as brianlist answer