Math, asked by Albert01, 1 year ago

anybody help me........

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Anonymous: nice handwriting!
Anonymous: better than mine...

Answers

Answered by ziafat111
2
let us take LHS=cosx/1-sin²x
=cosx/cos²x
=1/cosx
=secx=RHS

ziafat111: wlcm bro
Answered by amannewton
1
this is ur answer.......
hope it helped u

=cos^2x 1/cosx
=cos^2x. 1/cosx
=cos^2x
LHS=cos^2x

identically this equation is true
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