Question

anybody is there who solve this problem in his/ her notes​

Answer 1

Given that AB II CD

So BC is the transversal

75= y+25(alternate angles angles are equal )

75-25= y

50°=y

CD || EF(given in the question)

so CF is the transversal

x+25= 180°(sum of interior angles on the same side of transversal is 180°)

x= 180-25

x = 155°

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Answer 2

Step-by-step explanation:

Given :-

AB || CD || EF

(Attachment )

To find :-

Find the values of x and y ?

Solution :-

Given that

AB || CD || EF

< ABC = 75°

< DCF = 25°

< EFC = x

< FCB = y

I) CD || EF

On extending EF to H

=> CD || EH

and CF is a transversal.

<EFC and < DCF are the interior angles on the same side to the transversal.

We know that

The interior angles on the same side to the transversal are supplementary.

=> <EFC + < DCF = 180°

=> x + 25° = 180°

=> x = 180° -25°

=> x = 155°

Therefore, x = 155°

and

AB || EF

On extending AB to G

On extending CD to I

=> AG || DI

and BC is a transversal.

<ABC and < BCD are the alternative interior angles.

We know that

Alternative interior angles are equal.

=> <ABC = < BCD

=> <ABC = < BCF + < FCD

=> 75° = y+25°

=> y = 75°-25°

=> y = 50°

Therefore, y = 50°

Answer:-

The values of x and y are 50° and 155° respectively.

Used formulae:-

If two parallel lines Intersected by a transversal then

→ The interior angles on the same side to the transversal are supplementary.

→ Alternative interior angles are equal.