Question

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(Q) An object travels 16 m in 4 s and then another 16 m in 2 s. what is the average speed of the object?​

Answer 1

Explanation:

Answer

Total distance covered S=16+16=32 m

Total time t=4+2=6 s

Average speed V

avg

=

t

S

=

6

32

=5.33 m/s

Answer 2

$\pink{\underline{\underline{\mathfrak{\red{Given}}}}}:-$

• An object travels 16m in 4s.
• Another 16m in 2s.

$\pink{\underline{\underline{\mathfrak{\orange{To\:Find}}}}}:-$

• Average speed of the object.

$\pink{\underline{\underline{\mathfrak{\blue{Formula\:used}}}}}:-$

• $\sf{V_{avg} = \dfrac{S}{t}}$

$\pink{\underline{\underline{\mathfrak{\purple{Solution}}}}}:-$

$\star\:{\underline{\sf{Total\: distance\: covered}}}\::-$

$\longrightarrow\:\:\bf{S = 16+16}$

$\longrightarrow\:\:\bf{S =32\:m}$

$\star\:{\underline{\sf{Total\:time}}}\::-$

$\longrightarrow\:\:\bf{t = 4 + 2}$

$\longrightarrow\:\:\bf{t = 6\:s}$

$\star\:{\underline{\sf{Average\:speed}}}\::-$

$\longrightarrow\:\:\bf{V_{avg} = \dfrac{S}{t}}$

$\longrightarrow\:\:\bf{V_{avg} =\dfrac{32}{6}}$

$\longrightarrow\:\:\bf\green{V_{avg} =5.33\:m/s}$