Question

anybody knows that k no. answer??it is opt math question ​

Answer 1

Answer:

hey here is your solution

pls mark it as brainliest

Step-by-step explanation:

$to \: prove = \\ \frac{1 - tan \: \beta }{1 + tan \: \beta } = \frac{cot \: \beta - 1}{cot \: \beta + 1} \\ \\ so \: let \: LHS = \frac{1 - tan \: \beta }{1 + tan \: \beta } \\ \\ RHS = \frac{cot \: \beta - 1}{cot \: \beta + 1} \\ \\ considering \: LHS \\ = \frac{1 - tan \: \beta }{1 + tan \: \beta } \\ \\ = \frac{1 - \frac{1}{cot \: \beta } }{1 + \frac{1}{cot \: \beta } } \\ \\ = \frac{ \frac{ \frac{cot \: \beta - 1}{cot \: \beta } }{cot \: \beta + 1} }{cot \: \beta } \\ \\ = \frac{cot \: \beta - 1}{cot \: \beta + 1} \\ \\ thus \: LHS=RHS \\ hence \: proved$