Physics, asked by vishmish34, 6 hours ago

Anybody Pl. help to solve this question.
an electric iron of power 2 kW is used for 3 h per day. How much energy does it consume in 2 days? Express in joule.

Answers

Answered by taanyagupta242

0

Explanation:

W=P×t

1kW-h=3600kJ

2kW×6h=12kW-h=12×3600kJ=43200kJ

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