Anybody Pl. help to solve this question.
an electric iron of power 2 kW is used for 3 h per day. How much energy does it consume in 2 days? Express in joule.
Answers
Answered by
0
Explanation:
W=P×t
1kW-h=3600kJ
2kW×6h=12kW-h=12×3600kJ=43200kJ
Similar questions