anybody please helpe out
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tan² A + cot² A
= sec² A - 1 + cosec² A - 1
= sec² A + cosec² A - 2
= (1/cos ² A) + (1/sin² A) - 2
= (sin² A + cos² A)/(sin² A . cos² A) - 2
= (1/sin² A . cos² A) - 2
= sec² A . cosec² A - 2
= RHS
NOTE: Theta replaced by A
= sec² A - 1 + cosec² A - 1
= sec² A + cosec² A - 2
= (1/cos ² A) + (1/sin² A) - 2
= (sin² A + cos² A)/(sin² A . cos² A) - 2
= (1/sin² A . cos² A) - 2
= sec² A . cosec² A - 2
= RHS
NOTE: Theta replaced by A
shiny209:
should i replace theta by a in exams?
can u click a pic and send me i cant understand from division part
in the fifth line u typed
I just wrote sin² A + cos² A as 1. And you shouldn't replace theta by A in exam. I just didn't have theta in keyboard so I replaced.
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