anybody please say this answer
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ΔPSQ & ΔPSR
PQ= PR (GIVEN)
PS=PS ( COMMON SIDE)
<PSQ= <PSR ( RIGHT ANGLE)
ΔPSQ= ΔPSR (RHS)
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In triangle PSQ and triangle PSR
PQ = PR ( GIVEN)
ANGLE PSQ = ANGLE PSR (90° EACH)
PS = PS (COMMON)
THEREFORE, TRIANGLE PSQ = TRIANGLE PSR (BY RHS RULE)
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