Question

Anybody plz help me .....??:-(

Answer 1

In figure 51
x=60
Bcz
Angle AOB+Angle APB =180
120+APB=180
APB=60
In figure 53
x=60
angle MON =360-240
= 120
angle MON+angle x =180
120+x=180
×=60
In figure 54
angle CAB+ABC+x=180
50+90+x=180 (angle subtended in a semicircle on any point of the circle is 90)
140+x=180
x=40
I think that in figure 52
the angle might be 120