Question

anybody solve this

x Dy/dx+y=x^3

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Answer 1

⭐Solution ⭐

✏given here

x dy/dx + y = x³

=> dy/dx +y/x= x²

✒compaire by dy/dx +Px =Q

here ,

P = 1/x,

Q = x²

so,

I.f. = e^(interaction of P DX)

= e^(integration 1/x DX)

= e^(log x )

= x.

so,

solution will be

y ×I.f . = [ integrations of Q× I.f. DX

yx = [ integrations x²×x dx)

= (x⁴/4)

=> 4yx = x⁴.

✔Hopes its help's u.