anyone 9th here please explain me the lesson triangle. subject is geometry please Tomorrow is my exam please
Answers
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Answer:
Hey friend..
Wishing you all the best for your exam...
Step-by-step explanation:
9th std Triangles lesson is all about various congruence rules you have learnt in your lower grades.
Congruence rules:
→ (SAS congruence rule)
→ (ASA congruence rule)
→(SSS congruence rule)
→ (RHS congruence rule)
Case 1: If any two adjacent sides of the given triangles and the angle included between them are equal, then, both the triangles are said to be congruent by Side Angle Side Congruence Rule.
Case 2: If two angles along with the included side of both the triangles are equal, then, both the triangles are said to be congruent by Angle Side Angle Rule (AAS).
Case 3: If two angles and any one side of both the triangles are equal, then, both the triangles are said to be congruent by Angle Angle Side Rule (AAS).
Case 4: If all three sides of both the triangles are equal, then, the two triangles are said to be congruent by Side Side Side Rule (SSS).
Case 5: If the hypotenuse and one side of two right angle triangle are equal, then, both the triangles are said to be congruent by Right Hand Side Rule (RHS).
In this lesson, we are learning about these congruencies and proving them in various figures. Their proofs are very important.
These are some important questions you have in your textbook. Please do refer it.
Important Questions
Q.1) ABCD is a quadrilateral where BC = AD and ∠DAB = ∠CBA.
FIG.1
Prove that
(i) BD = AC
(ii) ∆ ABD ≅ ∆ BAC
(iii) ∠ ABD = ∠ BAC
Q.2) l and m are two parallel lines intersected by another pair of parallel lines p and q.
FIG.2
Prove that ∆ ABC ≅ ∆ CDA.
Q.3) In figure below, AC = AE, AB = AD and ∠ BAD = ∠ EAC.
FIG.3
Prove that BC = DE.
Also, solve all other examples and exercise questions from your textbook.
Do not worry and be confident..Tomorrow's exam will be easy.
