Question

Anyone answer as soon as possible
Q. 17

Answer 1

hey friend , here is ur solution
BD=EC(give)
add DE on both sides
BD+DE=EC+DE
we get EB = CD consider it equation 1
now , AD=AE(given)
so ,Angle ADE=Angle AED(angles opposite to equal sides are equal ) consider it as equation 2
now in ∆ABE and ∆ACD
BE=DC(using equation 1)
angle ADE=angle AED (using equation 2)
AD=AE(given)
so ∆ABE is congruent to ∆ACD (by SAS criterion)

Answer 2

According to question,
ad=ae     ---------1
bd=ec
in both triangle,
de is common---------2
angle ade = angle aed (due to ad = ae)---------3

1,2&3 as we know that, two sides and the angle between them(SAS rule)
abe=ade