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The possible length and breadths of the rectangle are the factors of the equation. i.e.
x^2-3x-4=0
x^2+x-4x-4= 0
(x+1)(x-4)=0
Therefore possible pair of sides are
x+1 , x+4
1 , (x+1)(x+4)
You can consider any of them as length and breadth and thus you will get 4 pairs.
Please mark it as brainliest.
Answered by
0
Answer:
a
Step-by-step explanation:
answer of your question is (x+1)(x+4)
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