Anyone answer please. It has to be proved
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LHS = sin(5π/6+x) + sin(5π/6-x)
consider sin(A+B) and Sin(A-B) formulae
= Sin(5π/6)cosx + Cos(5π/6)Sinx + Sin(5π/6)cosx - Cos(5π/6)Sinx
= 2Sin(5π/6) cosx
= 2Sin(π-(π/6))cosx
=2 sin(π/6) cosx
= 2 × (1/2)cosx
=Cosx
=RHS
Please check this once. I just gave a try
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