Question

Anyone answer this???​

Answer 1

Answer:

${3}^{(2 + \frac{1}{2n}) }$

Step-by-step explanation:

${( \frac{ {9}^{(n + \frac{2}{4}) }. \sqrt{3. {3}^{ - n} } }{3. \sqrt{ {3}^{ - n} } } )}^{ \frac{1}{n} } \\ \\ {( \frac{ {3}^{2(n + \frac{1}{2 } )} . \sqrt{ {3}^{(1 - n)} } }{3. {3}^{ ( - \frac{n}{2} )} } )}^{ \frac{1}{n} } \\ \\ { (\frac{ {3}^{(2n + 1)} . {3}^{ (\frac{1 - n }{2} )} }{ {3}^{(1 - \frac{n}{2} )} }) }^{ \frac{1}{n} } \\ \\ {( {3}^{(2n + 1 + \frac{1 - n}{2} ) }. {3}^{ (\frac{n}{2} - 1)} ) }^{ \frac{1}{n} } \\ \\ { {3}^{(2n + 1 + \frac{1}{2} - \frac{n}{2} + \frac{n}{2} - 1) } } ^{ \frac{1}{n} } \\ \\ { {3}^{(2n + \frac{1}{2}) } }^{ \frac{1}{n} } \\ \\ {3}^{(2 + \frac{1}{2n}) }$

If my answer is right then do nothing .

If my answer is wrong then report it.

Answer 2

${ (\frac{ {9}^{n + \frac{2}{4} } . \sqrt{3. {3}^{ - n} } }{3. \sqrt{ {3}^{ - n} } } )}^{ \frac{1}{n} } \\ \\ {( \frac{ {3}^{2(n + \frac{1}{2} )} . {3}^{ \frac{1}{2} }. {3}^{ \frac{ - n}{2} } }{3. {3}^{ \frac{ - n}{2} } }) }^{ \frac{1}{n} } \\ \\ { (\frac{ {3}^{2n + 1} . {3}^{ \frac{1}{2} } }{3} )}^{ \frac{1}{n} } \\ \\</p><p> { ({3}^{2n + 1 + \frac{1}{2} - 1 } )}^{ \frac{1}{n} } \\ \\ {( {3}^{2n + \frac{1}{2} }) }^{ \frac{1}{n} } \\ \\ {3}^{(2 + \frac{1}{2n} )}$