Question

Anyone answer this??​

Answer 1

Answer:

0

Step-by-step explanation:

$x = \frac{1}{5 + 2 \sqrt{6} } \\ \\ \frac{(5 - 2 \sqrt{6}) }{(5 + 2 \sqrt{6} )(5 - 2 \sqrt{6} )} \\ \\ \frac{5 - 2\sqrt{6} }{ {(5)}^{2} - {(2 \sqrt{6} )}^{2} } \\ \\ \frac{5 - 2 \sqrt{6} }{25 - 4.6} \\ \\ \frac{5 - 2 \sqrt{6} }{25 - 24} = 5 - 2 \sqrt{6}$

So, x²

${(5 - 2 \sqrt{6}) }^{2} \\ \\ {(5)}^{2} - 2.5.2 \sqrt{6} + {(2 \sqrt{6} )}^{2} \\ \\ 25 - 20 \sqrt{6} + 24 \\ \\ 49 - 20 \sqrt{6}$

Now, x² - 10x + 1 =

$(49 - 20 \sqrt{6} ) - 10(5 - 2 \sqrt{6} ) + 1 \\ \\ 49 - 20 \sqrt{6} - 50 + 20 \sqrt{6} + 1 \\ \\ 50 - 50 = 0$

If my answer is right then do nothing .

If my answer is wrong then report it .

Answer 2

Answer:

0

Step-by-step explanation:

$x = \frac{1}{5 + 2 \sqrt{6} } \\ \\ \frac{(5 - 2 \sqrt{6}) }{(5 + 2 \sqrt{6} )(5 - 2 \sqrt{6} )} \\ \\ \frac{5 - 2\sqrt{6} }{ {(5)}^{2} - {(2 \sqrt{6} )}^{2} } \\ \\ \frac{5 - 2 \sqrt{6} }{25 - 4.6} \\ \\ \frac{5 - 2 \sqrt{6} }{25 - 24} = 5 - 2 \sqrt{6}$

So, x²

${(5 - 2 \sqrt{6}) }^{2} \\ \\ {(5)}^{2} - 2.5.2 \sqrt{6} + {(2 \sqrt{6} )}^{2} \\ \\ 25 - 20 \sqrt{6} + 24 \\ \\ 49 - 20 \sqrt{6}$

Now, x² - 10x + 1 =

$(49 - 20 \sqrt{6} ) - 10(5 - 2 \sqrt{6} ) + 1 \\ \\ 49 - 20 \sqrt{6} - 50 + 20 \sqrt{6} + 1 \\ \\ 50 - 50 = 0$

I hope it will help you.