Question

Anyone answer this....​

Answer 1

Hey Buddy

Here's the Answer

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We know

1^3 + 2^3 + 3^3 +.........+ n^3 = ( n ( n + 1 )/2 )^2

So, Now we have

log[ ( n ( n + 1 )/2 )^2 ]

Now we know

• log a^n = n log a
• log ab = log a + log b
• log a/b = log a - log b

By applying above properties

2 [log(( n ( n + 1 )/2 )) ]

2[log n + log(n + 1 ) - log 2]

2 log n + 2 log (n + 1) - 2 log 2

Hence, option ( c ) is correct

PEACE

:)

Answer 2

Answer:

According to me answer is a.

Step-by-step explanation:

We know that ,

1³ + 2³+3³.....n³ = [n²(n+1)²]/4

so , log(1³ + 2³+3³.....n³)

= log[n²(n+1)²]/4

= [ log n² + log (n+1)² ] - log 4

= 2 log n + 2 log (n+1) - log 2²

= 2 log n + 2 log (n+1) - 2 log 2

Using formula

• log a² = 2 log a
• log ab = log a + log b
• log a/b = log a - log b