anyone answer this. kindly avoid giving stupid answers..a request
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Given
Condition =N.t.p
Gamma(¥)=1.4
Let initial volume= v1
Then final volume =1/32 v1
As we know
P1v1^¥=P2v2^¥
For n.t.p initial pressure =1bar
Hence
1xv1^1.4=P2v2^1.4
(V2=1/32V1)
V^1.4=(1/32 V1) ^1.4 XP2
P2= v1^1.4/ (0.03125v1) ^1.4
P2=128bar
This is ur ans hope it will help you in case of any doubt comment below
Condition =N.t.p
Gamma(¥)=1.4
Let initial volume= v1
Then final volume =1/32 v1
As we know
P1v1^¥=P2v2^¥
For n.t.p initial pressure =1bar
Hence
1xv1^1.4=P2v2^1.4
(V2=1/32V1)
V^1.4=(1/32 V1) ^1.4 XP2
P2= v1^1.4/ (0.03125v1) ^1.4
P2=128bar
This is ur ans hope it will help you in case of any doubt comment below
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