Question

Anyone answer this question With complete explanation
No Tukka allowed

Answer 1

SoLuTiOn :

➡ Given:

✏ Two small identical spheres of charges +10$\mu$C and -90$\mu$C attract each other with a force of F newton.

✏ They are kept in contact and then separated by the same distance.

➡ To Find:

✏ New force between them after separation.

➡ Concept:

✏ As per coulomb's law, The magnitude of electrostatic force between two point charges is directly proportional to the product of charges and inversely proportional to the square of the distance between them.

✏ Here distance between two chargea is same for both cases.

✏ Therefore, $\boxed{\bold{\rm{\pink{F\propto\:q_1\times{q_2}}}}}$

➡ Calculation:

• First case:

$\mapsto \rm \: F \propto \: q_1 \times q_2 \\ \\ \mapsto \rm \: F \propto \: 10 \times ( - 90) \\ \\ \mapsto \rm \: \red{F \propto \: 900} \: ......(1)$

• For second case:

$\mapsto \rm \: new \: charge \:on \: each \: sphere = \frac{q_1 + q_2}{2} \\ \\ \mapsto \rm \: q'_1 = q'_2 = q' = \frac{10 - 90}{2} = - 40 \mu{C} \\ \\ \mapsto \rm \: F' \propto \: q'_1\times{q'_2} \\ \\ \mapsto \rm \: {F' \propto \: ( - 40) \times ( - 40)} \\ \\ \mapsto \rm \: \blue{ F' \propto \: 1600} \: .....(2)$

✏ by taking (2)/(1)

$\mapsto \rm \: \frac{F'}{F} = \frac{16 \cancel{00}}{9 \cancel{00} } \\ \\ \mapsto \: \underline{ \boxed{ \bold{ \rm{ \orange{F' = \frac{16}{9} F}}}}} \: \star$

➡ Additional information:

• Coulomb's law also known as inverse square law.

Answer 2

$\large \underline{ \green{ \boxed{ \bf \blue{Required \: Answer}}}}$