anyone can give me answer
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Answered by
1
Answer:
26
Step-by-step explanation:
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Answered by
2
Answer:
Let first term be a and common difference d.
Using formula :
S_n = n / 2 ( 2 a + ( n -1 ) d )
150 = 10 / 2 ( 2 a + 9 d )
30 = 2 a + 9 d
2 a = 30 - 9 d ... ( i )
126 = 9 / 2 ( 2 a + 8 d )
14 × 2 = 2 a + 8 d
2 a = 28 - 8 d ... ( ii )
From ( i ) and ( ii )
30 - 9 d = 28 - 8 d
2 = d
2 a = 28 - 8 d ... ( ii )
2 a = 28 - 16
a = 6
Now :
Using formula :
t_n = a + ( n - 1 ) d
a = 6
d = 2
n = 10
t_10 = 6 + 9 × 2
t_10 = 6 + 18
t_10 = 24.
Final answer is 24.
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