anyone can solve it...
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1
24000×14×2÷100=6720
24000×14×9÷100÷12=2520
+24000=33240
24000×14×9÷100÷12=2520
+24000=33240
Answered by
1
p = 24000rs
r = 14% p. a.
t = 2 years+ 3/4 years
so we we will find out 2 years compound interest first
a = p(1+r/100)^n = 24000(1+14/100)^2 = 24000(114/100)^2 = 31190.4rs
and for the rest 3/4 it will be p = 31190.4rs
si = prt/100 = 311190.4*14*3/4*100 = 3274.9rs
total amount = 34465.39rs
or
si = prt/100
si = 24000*14*11/4*100 = 9240rs
amount will be 33240rs
r = 14% p. a.
t = 2 years+ 3/4 years
so we we will find out 2 years compound interest first
a = p(1+r/100)^n = 24000(1+14/100)^2 = 24000(114/100)^2 = 31190.4rs
and for the rest 3/4 it will be p = 31190.4rs
si = prt/100 = 311190.4*14*3/4*100 = 3274.9rs
total amount = 34465.39rs
or
si = prt/100
si = 24000*14*11/4*100 = 9240rs
amount will be 33240rs
Ron1111:
but answer is 33240
what is the answer in your textbook plz tell
okk but compound interest to amount will be this
srry, can't understand....
u can't understand that
actually when u found the compound interest u will have to do like this
ohh okk...
i hope u could understand me
yeah ,thank you very much...
g. n. bro
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