Question

Anyone can solve question 7 ....please​

Answer 1

Answer:

Given √2 is an rational number,(5+3√2)is rational number

(5+3√2)is rational

(5-5+3√2)us rational number

But this contradiction is 5+3√2is rational number

Hence (5+3√2) is an irrational number

Answer 2

Answer:

√2 is rational number

Let 5+3√2 is a rational number

so, 5 +3√2=a/b , where a and b is co prime integer .

then,3√2=a/b-5

3√2=a-5b/b

√2=a-5b/b×3

where a-5b/b×3 is rational number

but , we know that √2 is also irrational number

so, our statement is wrong of 5+3√2 is rational number

since ,it is irrational number