Anyone can solve question 7 ....please
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Given √2 is an rational number,(5+3√2)is rational number
(5+3√2)is rational
(5-5+3√2)us rational number
But this contradiction is 5+3√2is rational number
Hence (5+3√2) is an irrational number
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√2 is rational number
Let 5+3√2 is a rational number
so, 5 +3√2=a/b , where a and b is co prime integer .
then,3√2=a/b-5
3√2=a-5b/b
√2=a-5b/b×3
where a-5b/b×3 is rational number
but , we know that √2 is also irrational number
so, our statement is wrong of 5+3√2 is rational number
since ,it is irrational number
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