Question

anyone can u solve this question from theory of equation​

Answer 1

Answer:

(b^2-2ac)/(ac)^2

Step-by-step explanation:

Put x1 in quadratic equation we will get

x1(ax1+b) + c= 0

(ax1+b)= -c/x1

similarly

(ax2+b)= -c/x2

to find-

(x1/c)^2 + (x2/c)^2

= (x1^2 + x2^2)/c^2

= {(x1+x2)^2-2x1x2}/c^2

={(-b/a)^2-2c/a}/c^2

=(b^2-2ac)/(ac)^2

Now here we used the property of roots that product of roots is = c/a

and sum of roots = -b/a

and x1^2 + x2^2 = (x1+x2)^2 - 2x1x2