Question

anyone genuis here please solve this.

Answer 1

Since, a,b,c,d,e,f are in AP.Let us consider the common difference as 'x'.

Let a = x.

⇒ b = x + d

⇒ c = x + 2d

⇒ d = x + 3d

⇒ e = x + 4d

⇒ f = x + 5d.

Given:

⇒ e - c

⇒ x + 4d - (x + 2d)

⇒ 4d - 2d

⇒ 2d.

Therefore, e - c = 2d.

Hope this helps!

Answer 2

Given,

a, b, c, d, e ,f are  in AP.

If  the common difference between terms is  x

Then,

b -a = c - b = d - c  = e - d = f - e = x

∴ d - c = e -d

d + d = e - c

e - c = 2d