anyone give me answer.
Attachments:
Answers
Answered by
0
take x in theta place
tan ( π cos x ) = cot ( π sin x )
tan ( π cos x ) = tan [ ±(π/2) - π sin x ] ... ... cot θ = tan ( ±π/2 - θ )
π cos x = ±(π/2) - π sin x
cos x = ±(1/2) - sin x
cos x + sin x = ± (1/2)
Multiplying both sides by ( 1/√2 ),
( cos x )( 1/√2 ) + ( sin x )(1/√2 ) = ± 1 / (2.√2 )
( cos x )( cos π/4 ) + ( sin x )( sin π/4 ) = ± 1 / (2.√2 )
cos ( x - π/4 ) = ± 1 / ( 2.√2 ) .....................................
tan ( π cos x ) = cot ( π sin x )
tan ( π cos x ) = tan [ ±(π/2) - π sin x ] ... ... cot θ = tan ( ±π/2 - θ )
π cos x = ±(π/2) - π sin x
cos x = ±(1/2) - sin x
cos x + sin x = ± (1/2)
Multiplying both sides by ( 1/√2 ),
( cos x )( 1/√2 ) + ( sin x )(1/√2 ) = ± 1 / (2.√2 )
( cos x )( cos π/4 ) + ( sin x )( sin π/4 ) = ± 1 / (2.√2 )
cos ( x - π/4 ) = ± 1 / ( 2.√2 ) .....................................
Similar questions