Math, asked by hiteshpal, 1 year ago

anyone give me answer.

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Answered by harshdeeps50
0
take x in theta place

tan ( π cos x ) = cot ( π sin x ) 

tan ( π cos x ) = tan [ ±(π/2) - π sin x ] ... ... cot θ = tan ( ±π/2 - θ ) 

π cos x = ±(π/2) - π sin x 

cos x = ±(1/2) - sin x 

cos x + sin x = ± (1/2) 

Multiplying both sides by ( 1/√2 ), 

( cos x )( 1/√2 ) + ( sin x )(1/√2 ) = ± 1 / (2.√2 ) 

( cos x )( cos π/4 ) + ( sin x )( sin π/4 ) = ± 1 / (2.√2 ) 

cos ( x - π/4 ) = ± 1 / ( 2.√2 ) .....................................
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