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Let us assume our dividend function to be f(x) and divisor function as g(x).
For the above mentioned question
f(x)= x¹°°
g(x)= x+1
Now we equate g(x)=0 and find its roots. In our case
x+1=0 => x=-1 is a root.
Putting the value of x in f(x) we get
f(-1)= (-1)¹°°
f(-1)= 1
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