Question

Anyone help matching these?

Answer 1

Answer:

1) 22.4 L of CO2 gas -----> 1 mole  { Under S.T.P conditions }

2) 49g of H2SO4 -----> 0.5 moles  

   Molecular wt. of H2SO4 = 98g

   No.of moles = given wt./ molecular wt.

   n = 49 / 98

   n = 0.5 moles

3) 12.044 x 10^23 molecules of N2 ----> 2 moles

    1 mole = 6.022 x 10^23 molecules

4) 5.6 L of vinegar ----> 0.25 moles

    1 mole of vinegar at S.T.P conditions occupy 22.4L .

    =>   5.6 L of vinegar occupy = (1 / 22.4)x5.6 = 1/4 = 0.25 moles

5) 4g of NaOH ----> 0.1 moles

   Molecular wt. of NaOH = 40g

   No.of moles = given wt./ molecular wt.

   n = 4 / 40

   n = 0.1 moles

Hope it is useful...

Answer 2

☆[ANSWER]☆

1. 22.4 L of CO2 gas = 0.5 moles

2. 49g of H2 SO4 = 1mole

3. 12.044 × 10^23 molecules of N2 = 2moles

4. 5.6 L of vinegar = 0.25 moles

5. 4g of NaOH = 0.1 mole

Hope it helps UHHH!!!!