Question

Anyone Here to Answer The Question which is given below With diagram.

1. X and Y are respectively the mid-point of sides AB and BC of a parallelogram ABCD. DX and DY intersect AC at M and N respectively. If AC=4.5 cm, find MN. ​

Answer 1

Answer:

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Answer 2

Answer:

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ABCD is a parallelogram.

X and Y are mid points of the sides AB And BC respectively.

DY intersect AC at M and N respectively.

So XY = 1/2AC and XY || AC

(Mid point therom)

In ∆AOB X is the mid point of AB and XS || OM (XY || AC)

⇒OS = OB

⇒OD = OS + SB

⇒OD/OS = 2

⇒ OS/OD = 1/2

⇒ OS/OD +1 = 1/2 +1

⇒ (OS + OD) OD =3/2

⇒ OD/DS =2/3

⇒ OD/DS =3/2

⇒ ∆DMO~∆DNO (AA similarly)

So, Mo/XS = OD/DS

MO/XS =2/3

MO =2/3SY

similarly ON = 2/3SY

We get

= MO +ON =2/3 (XS+SY)

⇒ MN =2/3XY

MN =2/3 × 1/2AC

MN = 2/3 × 4.5/2

MN = 9/6

MN = 1.5 ..