Question

anyone here to solve this one​

Answer 1

Step-by-step explanation:

$\frac{ {x}^{2} - (x + 2)(x - 2) }{x + 3} = \frac{1}{2} \\ \frac{ {x}^{2} - ( {x}^{2} - 4) }{x + 3} = \frac{1}{2} \\ \frac{4}{x + 3} = \frac{1}{2} \\ 8 = x + 3 \\ x = 5$