anyone here who able to solve this question
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Given BAC =BDC
So by SAS triangle ABC similar to Triangle DCB
(ii) angle AEB =DEC(vertically opposite angles are equal)
So triangle ABE similar to Triangle DCE
So by SAS triangle ABC similar to Triangle DCB
(ii) angle AEB =DEC(vertically opposite angles are equal)
So triangle ABE similar to Triangle DCE
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