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Step-by-step explanation:
The cross section of a piece of metal 4m in length.
From C, draw CF || AB
then CF = AB = 10 cm
AF = CB = 7.5 cm
EF = EA - FA
=> 12 - 7.5
=> 4.5 cm
(i)
Now area of figure ABCDE (cross-section) = ar. (Rectangle ABCF) + ar. (Trapezium FCDE)
=> 10 * 7.5 + (1/2)(10 + 16) * 4.5
=> 75 + 58.5
=> 133.5 cm^2.
Area of cross-section = 133.5 cm^2.
(ii)
Length of piece = 4m = 400 cm.
Volume of the metal piece = Area * Length
=> 133.5 * 400
=> 53400 cm^3
Volume = 53400 cm^3.
(iii)
Weight of 1 cm^3 metal = 6.6
Total weight of the metal piece = 53400 * 6.6 = 352440 g = 3524.4 kg.
Weight of piece = 3524.4 kg
#I hope my answer helped you!
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