Math, asked by akankshamam, 1 month ago

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Answered by nazimhasan7863
1

Answer:

13). 2 {x}^{2}  + 2x +  {x}^{2}  + x \\  = 2 {x}^{2}  +  {x}^{2}  + 2x + x \\  = 3 {x}^{2}  + 3x \\ = 3x(x + 1)

14).5x +  {x}^{2}  - 2x +  {x}^{2}  \\  =  {x}^{2}  +  {x}^{2}  +  5x - 2x \\  = 2 {x}^{2}  + 3x

15).3x + 2x - x + 2 {x}^{2}  \\  = 2 {x}^{2}  + 3x + 2x - x \\  = 2 {x}^{2} + 4x \\  = 2x(x + 2)

6x  + 3 {x}^{2}  - x -  {x}^{2}  \\  = 3 {x}^{2}  -  {x}^{2}  + 6x - x \\  = 2 {x}^{2}  + 5x

17).4x + 3 +  {x}^{2}  - x \\  {x}^{2}  + 4x - x + 3 \\  =  {x}^{2}  - 3x + 3

18).2x + 3x + 9 + x \\  = 2x + 3x + x + 9 \\  = 7x + 9

19).2 {x}^{2}  + 3 + 3x - 1 \\ 2 {x}^{2}  + 3x + 3 - 1 \\  = 2 {x}^{2}  + 3x + 2

20).2x + 5 +  {x}^{2}  - x \\  =  {x}^{2}  + 2x - x + 5 \\  =  {x}^{2}   + x + 5

21).2x + 4y - x + y \\  = 2x - x + 4y + y \\  = x + 5y

22).2y + x + 3x - y \\  = x + 3x + 2y - y \\  = 4x + y

23).x + y + 2y - 4 \\  = x + 3y - 4

24).5 + 2x + y + 2x - 1 \\  = 2x + 2x + y + 5 - 1 \\  = 4x + y - 4

25).3y + 2 + 2y + 5 \\  = 3y + 2y + 2 + 5 \\  = 5y + 7

26).2x + 2y +  {x}^{2}  - x +  {x}^{2}  \\  =  {x}^{2}  +  {x}^{2}   + 2x - x + 2y \\  = 2 {x}^{2}  + x + 2y

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Answered by MehulNathani10
0

Answer:

L.H.S. = x2 – y2

= (p sec θ + q tan θ)2 – (p tan θ + q sec θ)2

= p2 sec θ + q2 tan2 θ + 2 pq sec 2 tan 2 -(p2 tan2 θ + q2 sec2 θ + 2pq sec θ tan θ)

= p2 sec θ + 2 tan2 θ + 2pq sec θ tan θ – p2 tan2 θ – q2 sec θ – 2pq sec θ tan θ

= p2(sec2 θ – tan2 θ) – q2(sec?2 θ – tan2 θ) =

= p2 – q2 …[sec2 θ – tan2 θ = 1

= R.H.S.hii

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