Question

anyone know how to solve​

Answer 1

Let A(2,1) and B(2,1) be the vertices of Δ

And C(x,y) be the third vertex

Area of ΔABC

.

.

.

But it is given that area of ΔABC=5.

.

.

3x+y=17 or 3x+y = -3 -----(1)

But it is given that third vertices lies on y = x +3

Hence subsisting value of y in (i)

3x + x +3 =17 or 3x + x +3 = -3

4x = 14. or. 4x = -6

x=7/2