Question

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Answer 1

Question:

• a parallel beam of light of wavelength lambda is incident normally on a narrow slit diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam at the second minimum of the difference action pattern the phase difference between the rays coming from the two edges of the slit is

Solution :

In case of diffraction the path difference for minima is given by the formula

$\implies \Delta \: x = n \lambda$

here , n = 2

$\implies \Delta \: x = 2 \lambda$

Phase difference is given by the formula ,

$\implies \phi = \frac{2\pi}{ \lambda} \times \Delta \: x$

$\implies \phi = \frac{2\pi}{ \lambda} \times 2\lambda$

$\boxed{ \phi = 4\pi}$