Question

Anyone of 8th class or elderly please help me with this question..!!!​

Answer 1

Answer:

$\frac{y(5 {y}^{2} - 125) }{5y(y - 5)} = \frac{5y( {y}^{2} - 25) }{5y(y - 5)} = \frac{({y}^{2} - 25) }{(y - 5)} = \frac{{(y - 5)}(y + 5)}{(y - 5)} = {(y + 5)}$

This is your answer....

Answer 2

${\huge {\mathfrak {Answer :-}}}$

We have, y(5y^2 - 125) / 5y(y - 5)

= y * 5(y^2 - 25) / 5y(y - 5)

= 5y(y + 5)(y - 5) / 5y(y - 5)

= (y + 5)

$<b>$ That's it..