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Answered by
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22. x+1=0
x=-1
p(x) = ax³+x²-2x+4a-9=0
p(-1)= a(-1)³+(-1)²-2(-1)+4a-9=0
= -1a+1+2+4a-9=0
= 3a-6=0
3a=6
a=6/3
a= 2
sry for taking time
x=-1
p(x) = ax³+x²-2x+4a-9=0
p(-1)= a(-1)³+(-1)²-2(-1)+4a-9=0
= -1a+1+2+4a-9=0
= 3a-6=0
3a=6
a=6/3
a= 2
sry for taking time
It's okay thanks tho
9th
wby?
Answered by
0
22) Given that x+1 is factor of p(x)
So, x= - 1
Putting the value of - 1 in p(x)
a(-1)^3+(-1)^2-2(-1)+4a-9=0
-a+1+2+4a-9=0
3a-6=0
a=2
SO,THEvalue of a is 2
if u satisfied please follow me
So, x= - 1
Putting the value of - 1 in p(x)
a(-1)^3+(-1)^2-2(-1)+4a-9=0
-a+1+2+4a-9=0
3a-6=0
a=2
SO,THEvalue of a is 2
if u satisfied please follow me
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