Question

Anyone please answer!!​

Answer 1

Answer:

first write 1 in numerator and denominator as identity in cot and cosec

Answer 2

❣️❣️$\textbf{\large{\pink{\underline{\underline{Step by step Explanation}}}}}$❣️❣️

$\mathrm{\large{\frac{cotA+cosecA-1}{cotA-cosecA+1}=\frac{1+cosA}{sinA}}}$

$\mathrm{\large{LHS=\frac{cotA+cosecA-1}{cotA-cosecA+1}}}$

$\mathrm{\large{=\frac{cotA+cosecA-(cosec^{2}A-cot^{2}A)}{cotA-cosecA+1}}}$

$\mathit{(cosec^{2}A-cot^{2}A=1)}$

$\mathrm{\large{=\frac{cotA+cosecA-(cosecA-cotA)(cosecA-cotA)}{cotA-cosecA+1}}}$

$\mathrm{\large{=\frac{cotA+cosecA(1-cotA+cosecA)}{(cotA-cosecS+1)}}}$

$\mathrm{\large{=cotA+cosecA}}$___(1)

$\mathcal{\underline{since,,}}$

$\mathrm{\large{RHS=\frac{1+cosA}{sinA}}}$

$\mathrm{\large{=\frac{1}{sinA}+}\frac{cosA}{sinA}}$

$\mathrm{\large{=cosecA+cotA}}$___(2)

$\textit{\underline{From (1) and (2),,}}$

$\mathrm{\large{LHS=RHS}}$

$\textit{Hence proved}$

$\textbf{\small{\red{\underline{Hope it helps you thanks}}}}$❣️❣️✌️✌️