Question

Anyone please answer 5th question. Don't post irrelevant answers.​

Answer 1

(i) For a person on the ground, the speed of ball will be the speed of train

therefore, v = 30 m / s

Mass = 100g = 0.1 kg

So,

$kinetic \: energy \: = \frac{1}{2} m {v}^{2}$

$\frac{1}{2} \times 0.1 \times {30}^{2}$

$45 \: joules$

(ii) For the person sitting in the train, the speed of ball will be 0

Mass = 100g = 0.1 kg

So,

$kinetic \: energy \: = \frac{1}{2} m {v}^{2}$

$\frac{1}{2} \times 0.1 \times {0}^{2}$

$0 \: joules$