Question

anyone please answer i will mark you as brainliest answer please be quick​

Answer 1

$\huge\sf\red{\underline{Answer}}$

${x}^{5} = ({ \frac{3}{7}) }^{ - 3} \times ({ \frac{3}{7}) }^{8} \\ = > {x}^{5} = ({ \frac{3}{7}) }^{(- 3)+ 8} <strong>[</strong><strong> </strong><strong>∵</strong><strong> </strong><strong>{</strong><strong>a</strong><strong>}^{</strong><strong>m</strong><strong>}</strong><strong> </strong><strong>×</strong><strong> </strong><strong>{</strong><strong>a</strong><strong>}^{</strong><strong>n</strong><strong>}</strong><strong> </strong><strong>=</strong><strong> </strong><strong>{</strong><strong>a</strong><strong>}^{</strong><strong>m</strong><strong>+</strong><strong>n</strong><strong>}</strong><strong> </strong><strong>]</strong><strong> </strong>\\ = > {x}^{5} = ({ \frac{3}{7}) }^{5}$

Equating the powers, we get,

$x = \frac{3}{7}$

Answer 2

$\huge{ \underline{ \bold{ᴀɴsᴡᴇʀ....{ \heartsuit}}}}$

$$\begin{lgathered}{x}^{5} = ({ \frac{3}{7}) }^{ - 3} \times ({ \frac{3}{7}) }^{8} \\ = > {x}^{5} = ({ \frac{3}{7}) }^{(- 3)+ 8} [ ∵ {a}^{m} × {a}^{n} = {a}^{m+n} ] \\ = > {x}^{5} = ({ \frac{3}{7}) }^{5}\end{lgathered}$$

Equating the powers, we get,

$$x = \frac{3}{7}$$