Question

anyone please answer the above question it's important(if not know please don't answer)​

Answer 1

Answer:

$a = \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \: \: , \: \: b = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ = \frac{ {( \sqrt{3} - \sqrt{2}) }^{2} }{ {( \sqrt{3}) }^{2} - {( \sqrt{2}) }^{2} } \: \: \: \: \: , \: \: \: \: \: \: = \frac{ {( \sqrt{3} + \sqrt{2}) }^{2} }{ {( \sqrt{3}) }^{2} - {( \sqrt{2}) }^{2} } \\ = \frac{3 + 2 - 2 \sqrt{6} }{3 - 2} \: \: \: \: \: , \: \: \: \: \: \: = \frac{3 + 2 + 2 \sqrt{6} }{3 - 2} \\ \boxed{a = 5 - 2 \sqrt{6}} \: \: \: \: \: \: , \: \: \: \: \: \: \: \boxed{ b= 5 + 2 \sqrt{6} }\\ \blue{ \underline{put \: the \: values \: in \: {eq}^{n} \: in\: {a}^{2} + ab + {b}^{2} }} \\ = {(5 - 2 \sqrt{6} )}^{2} + (5 - 2 \sqrt{6} )(5 + 2\sqrt{6} ) + {(5 + 2 \sqrt{6} )}^{2} \\ = 25 + 24 - 20 \sqrt{6} + 25 - 24 + 25 + 24 + 20 \sqrt{6} \\ = 25 + 24 + 25 + 25 \\ = 99 \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$