Question

Anyone Please Answer the question

5 parts 15 points (3 point for each)

Question>>>>>>>>
The primary coil of Ideal Step Up Transformer has 100 turns and Transformer ratio is also 100 the input voltage and power 220V , 1100W.

Find :-)

(i) Number of turns in secondary coil

(ii) Current in primary coil

(iii) Voltage across secondary coil.

(iv) Current in secondary coil.

(v) Power in secondary coil​

Answer 1

Here

Given that

$\sf N_p = 100 \\ \\ \sf k = 100 \\ \\ \sf E_p = 220V \\ \\ \sf P_{input} = P_p = 1100W$

Now,

$\sf(i) \: \: \: k = \dfrac{N_s}{N _p } \\ \\ \sf Ns = kN_p \\ \\ = 100 \times 100 \\ \\ = {10}^{4}$

$\sf (ii) \: \: \: P_p = E_pIp \\ \\ I_p = \sf \frac{P_p}{E_p} \\ \\ = \frac{1100}{220} \\ \\ = 5A$

$\sf(iii) \: \: \: k = \frac{E_s}{E_p} \\ \\ \sf E_s = kE_p \\ \\ \sf = 100 \times 220 = 2200 \\ \\ \sf E_s = 22000V$

$\sf (iv)E_sI_s = E_pI_p \\ \\ \sf I_s = \frac{E_pI_p}{E_s} = \frac{1}{20} \\ \\ \sf I_s = \frac{1}{20} A$

$\sf(v)P_{output} = P_s = E_sI_s \\ \\ = 22000 \times \frac{1}{20} \\ \\ P_s= 1100W$

Answer 2

Required Answer :-

(I) Number of turns in secondary coil

We know that

$\sf r = \dfrac{N_s}{N_p}$

$\sf 100 = \dfrac{N_s}{100}$

$\sf 100 \times 100 =N_s$

$\sf 10000 = N_s$

(II) Current in primary coil

$\sf I =\dfrac{P}{V}$

$\sf I=\dfrac{1100}{220}$

$\sf I= 5 \; A$

(III) Voltage across secondary coil.

$\sf r = \dfrac{V_s}{V_p}$

$\sf 100 = \dfrac{N_s}{220}$

$\sf 100 \times 220 = N_s$

$\sf 22000 = N_s$

(IV)  Current in secondary coil.

$\sf r =\dfrac{I_p}{I_s}$

$\sf 5 = \dfrac{100}{I_s}$

$\sf 5I_s = 100$

$\sf I_s = \dfrac{5}{100}$

$\sf I_s = 0.05$

(V)Power in secondary coil​

$\sf V_SI_S = V_PI_P$

$\sf V_SI_S = 22000\times 0.05$

$\sf V_SI_S = 1100$