Question

Anyone please answer the question correctly. Find the square root of the above expression​

Answer 1

Answer:

2cotx

Step-by-step explanation:

4 + 4 cot^2 x = 4(1 + cot^2 x) = 4 cosec^2 x

1 + tan^2 x = sec^2 x

$\sqrt{\frac{4 + 4 cot^{2}x }{1 + tan^{2}x}} = \sqrt{\frac{4cosec^{2}x}{sec^{2}x}} = \frac{2cosec x}{sec x} = \frac{4cosx}{sinx} = 2cotx$

Hope it helps :)

Answer 2

Answer:

first answer 4 csc$x^{2}$

the second is 0

Step-by-step explanation: