Question

anyone please answer the
question if you knows​

Answer 1

Answer:

cot (θ/2) ≥ μ is the answer.

Explanation:

N = Mg - Fcosθ

⇒ N = Mg - Mg cosθ

⇒ N = 2 Mg sin²(θ/2)

Further block can be pulled if,

F sinθ ≥ μN cosθ

⇒ 2Mg sin(θ/2) cos(θ/2) ≥ 2μMg sin²(θ/2)

⇒ cot (θ/2) ≥ μ

∴ cot (θ/2) ≥ μ

Answer 2

Answer:

opt d

Explanation:

so we have Fsinθ≥μN

 

we will get Ce of N we get Sinθ=μ(1−cosθ)  

we will atlast get option D as the answer.