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If S29 = 3538, a29 = 248, find the first term and the common difference
Answers
Answered by
0
Answer:
s - 122
a - 8.55
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Answered by
0
Answer:
answer is a = -4, d = 9
Step by step answer:-
Given that S29 = 3538 and a29 = 248,
so, Sn = n/2[ 2a + ( n-1) d], an = a + (n-1) d
put the value of n in their respective places, we get
s29= 29/2 [ 2a + 28d] = 3538 --------- ( I ),
a29 = 2a +28 d = 248 --------------------( ii ),
so, by second equation, we get 28d =248-a -------- ( iii ),
substituting value od 28d In first equation
we get 29/2( 2a-a +248),
by solving this we get, a = -4,
put the value of a in third equation, we get d = 9..
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