Question

anyone please give the solution and explanation for these two questions...,​

Answer 1

Answer:

see the explanation below with it's answer

Explanation:

Q. 1 )

Time period = $\frac{TOTAL \ OSCILLATION }{ TOTAL \ TIME \ TAKEN}$

$Time \ Period = \frac{40}{4}$

$Time \ Period = 10$

Q.2)

Frequency equals the number of waves that passes a given point per second or the number of oscillations of a vibrating body per second or number of cycles per second.

In this case, a mosquito vibrates its wings at an average rate of 500 vibrations per second. Therefore, the frequency of the sound is 500 Hz.

Time period of the wave is defined as the reciprocal of the frequency of the wave.

That is, T= $\frac{1}{f}$ $= \frac{1}{500} = 0.002 \ second$

$Hence, \ time \ period \ of \ the \ sound \ produced \ by \ the \ mosquito \ is \ 0.002 \ second.$

Hope It Helps You