anyone please give the steps what happens when we add equation (i) and (ii) to arrive at the conclusion AB²+AC²=2[AD² +(1/2BC)²]
Please solve it in a paper and send the picture of it
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We have, angle aed=90
ade is acute angle and angle ADC is obtuse
Since ADC is obtuse
ac*2=ad*2+DC*2+2dc.de
ac*2=ad*2+BC.de+1\4bc*2. (1)
Now Ade is acute angle in triangle and
ab*2=ad*2+bd*2-2bd.de
ab*2=ad*2-bc.de+1\4bc*2. (2)
Add 1&2
ab*2+ac*2=2ad*2+1\2bc*2
ade is acute angle and angle ADC is obtuse
Since ADC is obtuse
ac*2=ad*2+DC*2+2dc.de
ac*2=ad*2+BC.de+1\4bc*2. (1)
Now Ade is acute angle in triangle and
ab*2=ad*2+bd*2-2bd.de
ab*2=ad*2-bc.de+1\4bc*2. (2)
Add 1&2
ab*2+ac*2=2ad*2+1\2bc*2
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