Question

anyone please help me
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Answer 1

Solution :

In a parallelogram ABCD , Angle A = 3 times Angle B .

We have to find all the angles of the parallelogram .

In a parallelogram , one of its properties is that adjacent angles are supplementary .

That is , Angle A + Angle B = 180°

> 3 Angle B + Angle B = 180°

> 4 Angle B = 180°

> Angle B = 45° .

Angle A = 135°

In a parallelogram , vertically opposite angles eee also equal.

Thus , the angles become :

Angle A = 135°

Angle B = 45°

Angle C = 135°

Angle D = 45° .

Now ,

AB = 5x - 7

CD = 3x + 1

AB = CD

> 5x - 7 = 3x + 1

> 2x = 8

> x = 4

CD = 3 × 4 + 1 = 13 units .

This is the required answer .

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Answer 2

Answer:

Question :-

In a Parallelogram ABCD angleA = 3 times angle B. Find all angles of Parallelogram. If AB = 5x - 7 and CD = 3x + 1. Find CD

SoluTion :-

According to the Property of Parallelogram. Sum of two angle is supplementary angle.

Let angle B be x.

Angle A be 3x

$\sf \angle \: A + \angle B = 180$

$\sf \bigg(3x + x \bigg) = 180$

$\sf 4x = 180$

$\sf \: x \: = \dfrac{180}{4}$

$\sf \: x \: = 45$

Angle A = 3(45) = 135⁰

Angle B = 45⁰

Angle C = Angle A = 135⁰

Angle D = Angle B = 45⁰

Now,

AB = CD

5x - 7 = 3x + 1

5x - 3x = 7 + 1

2x = 8

x = 8/2

x = 4

CD = 3(4) + 1 = 12 + 1 = 13 units