Question

anyone please help me in solving question number second

Answer 1

let the sides of the rectangle be A and 3A,

then according to question, we have

Area = 300 me²,

A×3A=300,

then

3A²=100,

A²=100,

A=√100,

A=10,

then breadth=10 me,

length=3×10=30me,

therefore

perimeter of the rectangle=2(length+breadth),

=2(30+10),

=2×40=80me