Question

anyone please help me to solve 27th or question​

Answer 1

Answer:

hope it helps

please follow me if my answer is right

i shall be thankful

Answer 2

Answer:

$6 {y}^{2} - 7y + 2 \\ \alpha + \beta = \frac{7}{6} \\ \alpha \beta = \frac{1}{3} \\ \\ now \: we \: know \: {x}^{2} - ( \frac{1}{ \alpha } + \frac{1}{ \beta } )x + ( \frac{1}{ \alpha } \times \frac{1}{ \beta } ) \\ {x}^{2} - ( \frac{ \alpha + \beta }{ \alpha \beta } )x + (3) \\ {x}^{2} - ( \frac{7 \times 3}{6} )x + 3 \\ {x}^{2} - \frac{7}{2} x + 3 \\ or \\ 2 {x}^{2} - 7x + 6$